Python commandline template

Last updated 2021-06-28

Template for writing a new Python commandline script

Instead of writing execrable shell scripts, I write a lot of Python commandline scripts. I use this template as a starting point, which helps me remember a few things:

  • Just how the __name__ == "__main__" syntax and getting arguments from the commandline work.
  • The proper incantation for configuring logging.
  • The idb_excepthook() function, which I use to implement a --debug mode where the interactive debugger is started automatically if an unhandled exception is encountered.


Available directly at (shortened).

#!/usr/bin/env python3

import argparse
import logging
import os
import pdb
import sys
import traceback
import typing

    level=logging.INFO, format="[%(asctime)s] [%(name)s] [%(levelname)s] %(message)s"
logger = logging.getLogger(__name__)

def idb_excepthook(type, value, tb):
    """Call an interactive debugger in post-mortem mode

    If you do "sys.excepthook = idb_excepthook", then an interactive debugger
    will be spawned at an unhandled exception
    if hasattr(sys, "ps1") or not sys.stderr.isatty():
        sys.__excepthook__(type, value, tb)
        traceback.print_exception(type, value, tb)

def resolvepath(path):
    return os.path.realpath(os.path.normpath(os.path.expanduser(path)))

def parseargs(arguments: typing.List[str]):
    """Parse program arguments"""
    parser = argparse.ArgumentParser(description="Python command line script template")
        help="Launch a debugger on unhandled exception",
    parser.add_argument("action", help="The thing to do")
    parsed = parser.parse_args(arguments)
    return parsed

def main(*arguments):
    """Main program"""
    parsed = parseargs(arguments[1:])
    if parsed.debug:
        sys.excepthook = idb_excepthook
    print(f"Taking important action: {parsed.action}")

if __name__ == "__main__":